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Deleting a single point in a polygonal hotspot

Rylee

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Dienstag, 23. Juni 2015, 19:09

Deleting a single point in a polygonal hotspot

Hi,

I am writing a tool to draw on a krpano viewer. Part of this is dynamically creating polygonal hotspots, much like the example given in the "addhotspot" documentation.

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addhotspot(polyspot);
set(hotspot[polyspot].fillalpha, 0.25);
set(hotspot[polyspot].borderalpha, 0.50);
set(hotspot[polyspot].onclick, removehotspot(polyspot) );
set(hotspot[polyspot].point[0].ath,-10);
set(hotspot[polyspot].point[0].atv,-10);
set(hotspot[polyspot].point[1].ath,-10);
set(hotspot[polyspot].point[1].atv,+10);
set(hotspot[polyspot].point[2].ath,+10);
set(hotspot[polyspot].point[2].atv,+10);
set(hotspot[polyspot].point[3].ath,+10);
set(hotspot[polyspot].point[3].atv,-10);


The problem is that I cannot delete any of these points — how do I delete a single point? Is this even possible?

EDIT: things I have tried (that do not work):

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removehotspot(hotspot[polyspot].point[3])
delete(hotspot[polyspot].point[3])
delete(hotspot[polyspot].point['n3']
Rylee Fowler
Full Stack Developer, Devio, LLC.

jordi

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Dienstag, 23. Juni 2015, 19:51

I don't think you can remove a single point of polyhotspot, but I guess there are other options... Like giving the same position as the next or previous point...
everpano.com step beyond 360

Rylee

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3

Dienstag, 23. Juni 2015, 19:52

That would not help. My goal is to be able to delete any single added point.

Will I simply have to delete the whole hotspot and re-render it? That would be reasonably trivial.
Rylee Fowler
Full Stack Developer, Devio, LLC.

Alexey Tkachenko

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Dienstag, 23. Juni 2015, 22:45

I remember the "removearrayitem()" action from documentation. And here's the answer to your question, I hope:

programmatically remove points from polygonal hotspot
Regards,

Alexey

Rylee

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5

Donnerstag, 25. Juni 2015, 22:04

Hi Alexey,

Yes. That works perfectly!

Do note that you must call "updatescreen()" before this change will be graphically represented.
Rylee Fowler
Full Stack Developer, Devio, LLC.

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