Need help to convert from equirectangular to rx ry rz

nathan.nakamoto

Would some genius please help me this.
I have this image hotspot (yellow area):
(image 1)

It is descripted in kpt by 4 points:

<point x="0.572843" y="0.369941"/>
<point x="0.67479" y="0.370735"/>
<point x="0.675106" y="0.50119"/>
<point x="0.57254" y="0.501432"/>
When XML file is built, it looks like this:

It is descripted in XML:

<hotspot name="spotpicture53"
url="%FIRSTXML%/spots/spot.png"
distorted="true"
scale="1.0"
ath="44.169299"
atv="-2.496672"
width="244"
height="461"
rx="58.374289612600599"
ry="24.619635269375699"
rz="1.8306804508499752"
enabled="true"
capture="false"
handcursor="false"
/>
I tried to understand what math to convert 4 points of equirectangular to rx ry rz ath atv. At first, I thought ath atv is centroid of 4 points. However, it's not correct because it should be (44.55654,-11.53605). I also tried Cartesian coordinates but no luck. Would someone please shed some light to this or help me?
Much appreciation!

indexofrefraction

ath/atv (and depth) define the hotspot position in spherical coordinates (angles)
alternatively you could use tx/ty/tz for a 3D space definition
these will place the origin of the hotspot

the coordinates of a polygonal hotspot are just 2d, related to the origin of the hotspot

rx/ry/rz in conjunction with rotationorder describe the rotation of a hotspot
if you do not set rx/ry/rz the hotspot will be perpendicular to the center (camera)
sadly rotationorders are really tricky .-)
http://www.euclideanspace.com/maths/geometry/rotations/
http://www.euclideanspace.com/maths/geometry…euler/index.htm

equirectangular is a projection, not a rotation, what do you mean by "convert from equirectangular to a rotation" ?
also a polygonal hotspot can not be an image hotspot at the same time
you can not 3d define a polygonal hotspot, they are always 2d, like image hotspots

it is not really clear what do you want to do ...

nathan.nakamoto

Indexofrefraction, thank you for your quick response. Your question is exactly what I am trying to figure out. How is a quadrilaterals on equirectangular can be converted to 3D rotation. May be this image (please see the attachment) will help to clear my question a little bit more. Also, thank you for your links.

indexofrefraction

ahh.. hmm.. you want to exactly match the corners of the rectangle in the equirectangular image by using a hotspot?
i think this is very complex... the 2d coords of the equirectangular image correspond to ath/atv values.
but then point coordinates of a polygonal hotspots are 2d again and dont correspond to the ath/atv values ...

have a look at tuurs toolbox, with that you can place/roatate hotspots manually.
you can drag the hotspot (sets ath/atv) and tune rx/ry/rz until it fits.

https://krpano.com/forum/wbb/inde…74910#post74910

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